Waitrud Weber’s blog

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2019-01-31から1日間の記事一覧

formula 3000

so, we forcus on the bold below formula. 1/(a+b) = c/a + d/b c*b/a*b + a*d/a*b = ( c*b + a*d ) / a*b c*b + a*d = C a+b=C*a*b a + b = (c*b + a*d)*a* b the above looks also interesting. abc = 1 ...(1) abd = 1 ...(2) we could replace, bc = 1/…

formula 1

1/(a+b) = c/a + d/b a/(a+b) = c + d*a/b a= bc + ad ... (1) a+b = b ...(2) b or c equals 0 I hope c = 0 ... and don't know that. The above formula doesn't succeed. Because 1/2 = 2/4 But, it looks interesting. At least, 1/(a+b) = C*(c/a + d/…